Question

A large battery is a cylinder with the dimensions shown below. What is the total weight, rounded to the nearest gram, if the density of the battery is ?

Answer 1

Explanation:

Step 1. We have a cylinder with a radius of 4cm and a height of 10cm.

$\begin{gathered} r=4cm \\ h=10cm \end{gathered}$

And we also have the density of the cylinder:

$p=12\frac{g\text{ }}{cm^3}$

Step 2. We need to find the weight, which in this case is the mass of the cylinder, using the following formula:

$p=\frac{m}{V}$

where p is the density, m is the mass, and V is the volume of the cylinder.

Step 3. The volume is:

Substituting the known values and using

$\pi=3.1416$$V=(3.1416)(4cm)^2(10cm)$

Solving the operations

$V=502.656cm^3$

Step 3. Now we go back to our density formula:

$p=\frac{m}{V}$

and substitute the known values of the density and the volume:

$12\text{ }g/cm^3=\frac{m}{502.656cm^3}$

Solving to find the mass:

$\begin{gathered} 12g/cm^3\times502.656cm^3=m \\ \downarrow \\ 6,031.872g=m \end{gathered}$

rounding the mass to the nearest gram:

$6,032=m$

The mass in grams is 6,032.

Answer: 6,032