We are going to do this step by step:
Let's start with option A
A.
X = 25 and Y = 5/2
[tex]y=\frac{2}{5}\cdot x=\frac{2}{5}\cdot25=\frac{2\cdot25}{5}=\frac{50}{5}=\frac{5\cdot10}{5\cdot1}=10[/tex]
In this case, when X = 25 , then Y = 10 ,which is different to 5/2
B.
X = 14 , Y = 35
[tex]y=\frac{2}{5}\cdot14=\frac{28}{5}[/tex]
In case, when X = 14, then Y = 28/5, which is different to 35
C.
X = 40 , Y = 24
[tex]y=\frac{2}{5}\cdot40=\frac{80}{5}=16[/tex]
Similarly, in this case, when X = 40, then Y = 16, which is different to 24
D.
X = 10 , Y=4
[tex]y=\frac{2}{5}\cdot10=\frac{20}{5}=4[/tex]
Now, in this case, we can see that when X = 10, then Y = 4 which is the same as the given value of Y
E.
X = 50 , Y = 20
[tex]y=\frac{2}{5}\cdot50=\frac{100}{5}=20[/tex]
In this case, the values of Y are also the same.
F.
X = 30 , Y = 12
[tex]y=\frac{2}{5}\cdot30=\frac{60}{5}=12[/tex]
Again, in this case, the values of Y are the same, so the pair satisfies the equation.
In conclusion: options D, E and F satisfy the equation
