Start with simplifying the exponent
[tex]\begin{gathered} (\frac{3}{5})^2+4\times3-2 \\ \Longrightarrow\frac{9}{25}+4\times3-2 \end{gathered}[/tex]then get the product of 4 and 3
[tex]\begin{gathered} \frac{9}{25}+4\times3-2 \\ \Longrightarrow\frac{9}{25}+12-2 \end{gathered}[/tex]Then, add and subtract
[tex]\begin{gathered} \frac{9}{25}+12-2 \\ =\frac{9}{25}+10 \\ =\frac{9}{25}+\frac{250}{25} \\ \Longrightarrow\frac{259}{25} \\ \\ \text{therefore,} \\ (\frac{3}{5})^2+4\times3-2=\frac{259}{25} \end{gathered}[/tex]