Respuesta :

[tex]\begin{gathered} \text{Given} \\ (\frac{3}{5})^2+4\times3-2 \end{gathered}[/tex]

Start with simplifying the exponent

[tex]\begin{gathered} (\frac{3}{5})^2+4\times3-2 \\ \Longrightarrow\frac{9}{25}+4\times3-2 \end{gathered}[/tex]

then get the product of 4 and 3

[tex]\begin{gathered} \frac{9}{25}+4\times3-2 \\ \Longrightarrow\frac{9}{25}+12-2 \end{gathered}[/tex]

Then, add and subtract

[tex]\begin{gathered} \frac{9}{25}+12-2 \\ =\frac{9}{25}+10 \\ =\frac{9}{25}+\frac{250}{25} \\ \Longrightarrow\frac{259}{25} \\ \\ \text{therefore,} \\ (\frac{3}{5})^2+4\times3-2=\frac{259}{25} \end{gathered}[/tex]

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