Respuesta :

Notice that at x_0,

[tex]\begin{gathered} f(x_0)=6 \\ \text{and} \\ g(x_0)=4 \\ x_0\in domain\text{ of f(x)} \end{gathered}[/tex]

Therefore,

[tex]\begin{gathered} \Rightarrow g(x_0)=f(x_0)-2 \\ \Rightarrow g(x)=f(x)-2 \end{gathered}[/tex]

The answer is option C), g(x)=f(x)-2

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