Question

Question 12, pre calc, I’m at work so I’ll look at it later thanks

Answer 1

Given:

$\frac{14x^2-12x}{x+6}$

To find the zeros:

Let the numerator be equal to zero

$\begin{gathered} 14x^2-12x=0 \\ 2x\mleft(7x-6\mright)=0 \\ x=0,\frac{6}{7} \end{gathered}$

Hence, the zeros are,

$(\frac{6}{7},0),(0,0)$