Respuesta :

ASSUMPTIONS:

1) Let the even number be n.

2) Let the second of the 3 consecutive numbers be x. Therefore, we have the 3 consecutive numbers to be:

[tex](x-1),x,(x+1)[/tex]

PROOF:

We have that:

[tex]n=(x-1)+x+(x+1)[/tex]

Solving the right-hand side:

[tex]\begin{gathered} n=x-1+x+x+1 \\ n=3x \end{gathered}[/tex]

Since n is even, that means that x must be even.

We can get the value of x to by dividing both sides by 3 to get:

[tex]x=\frac{n}{3}[/tex]

Since x is an even whole number, n must be divisible by 3.

CHECK:

Try n = 18:

[tex]\begin{gathered} x=\frac{18}{3} \\ x=6 \end{gathered}[/tex]

Hence, the 3 numbers will be:

[tex]\begin{gathered} (6-1),6,(6+1) \\ \Rightarrow5,6,7 \end{gathered}[/tex]

The sum is:

[tex]5+6+7=18[/tex]

This proves the theory.

CONCLUSION:

For an even number to be able to be written as the sum of three consecutive whole numbers, it has to be DIVISIBLE BY 3.

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