ASSUMPTIONS:
1) Let the even number be n.
2) Let the second of the 3 consecutive numbers be x. Therefore, we have the 3 consecutive numbers to be:
[tex](x-1),x,(x+1)[/tex]PROOF:
We have that:
[tex]n=(x-1)+x+(x+1)[/tex]Solving the right-hand side:
[tex]\begin{gathered} n=x-1+x+x+1 \\ n=3x \end{gathered}[/tex]Since n is even, that means that x must be even.
We can get the value of x to by dividing both sides by 3 to get:
[tex]x=\frac{n}{3}[/tex]Since x is an even whole number, n must be divisible by 3.
CHECK:
Try n = 18:
[tex]\begin{gathered} x=\frac{18}{3} \\ x=6 \end{gathered}[/tex]Hence, the 3 numbers will be:
[tex]\begin{gathered} (6-1),6,(6+1) \\ \Rightarrow5,6,7 \end{gathered}[/tex]The sum is:
[tex]5+6+7=18[/tex]This proves the theory.
CONCLUSION:
For an even number to be able to be written as the sum of three consecutive whole numbers, it has to be DIVISIBLE BY 3.