If the chord of a circle is 24.5 in. long and subtends a central angle of 57.5 degrees what is the radius of the circle?(Do not round until the final answer. Then round to the nearest tenth as needed.)

Okay, here we have this:
Considering the provided information, and the following chord length equation, we obtain the following:
[tex]\begin{gathered} K=2r\cdot sen(\frac{\theta}{2}) \\ 24.5=2r\cdot\text{sen(}\frac{57.5}{2}\text{)} \end{gathered}[/tex]Now, let's solve for r:
[tex]\begin{gathered} 2r\sin \mleft(\frac{57.5^{\circ\:}}{2}\mright)=24.5 \\ r=\frac{24.5}{2\sin\left(28.75^{\circ\:}\right)} \\ r=25.5\text{ in} \end{gathered}[/tex]Finally we obtain that the radius of the circle is approximately 25.5 inches.