Given:
The principal amount is P = $6000.
The rate of interest is r = 12% = 0.012.
The number of years is t = 4.
For monthly compound interest, n = 12 per year.
The objective is to find the future value.
Explanation:
The general formula for compound interest is,
[tex]A=P(1+\frac{r}{n})^{nt}\text{ . . . . . . .(1)}[/tex]Substitute the given values in equation (1).
[tex]\begin{gathered} A=6000(1+\frac{0.012}{12})^{12(4)} \\ =6000(1+0.01)^{48} \\ =9673.356466\ldots. \\ \approx9673.36 \end{gathered}[/tex]Hence, the future value is $9673.36.