Question

How much heat in joules is needed to raise the temperature of 2.5 L of water from 0°C to 87.0°C? (Hint: Recall the original definition of the liter.)answer:____ J

Answer 1

Given:

Volume of water = 2.5 L

Initial temperature, T1 = 0°C

Final temperature, T2 = 87.0°C

Let's find the amount of heat needed in Joules.

Apply the specific heat Capacity formula:

$\begin{gathered} Q=mc\Delta T \\ \\ Q=mc(T_2-T_1) \end{gathered}$

Where:

C is the specific heat capacity of water = 4.187 kJ/g °C

To find the mass, m, we have:

1 L = 1 kg

2.5 L = 2.5 kg

Therefore, we have:

$\begin{gathered} Q=2.5*4.187*(87-0) \\ \\ Q=910.6725\text{ kJ}\approx910672.5\text{ J} \end{gathered}$

Therefore, the amount of heat needed is 910672.5 Joules.

ANSWER:

910672.5 J