A right triangle has side lengths 5, 12, and 13 as shown below.Use these lengths to find cos A, tan A, and sinA.cosA=tanA=sinA=

r = 13
y = 5
x = 12
cos A = theta (based on the image), then:
[tex]\cos \text{ A = }\frac{Adyacent\text{ of A}}{Hypothenus}\text{= }\frac{12}{13}\text{ }\approx0.92[/tex]tan A:
[tex]\tan \text{ A =}\frac{Opposite\text{ of A}}{\text{Adyacent of A}}\text{=}\frac{5}{12}\text{ }\approx\text{ 0}.42[/tex]sin A:
[tex]\sin \text{ A = }\frac{5}{13}\text{ }\approx0.38[/tex]