The probability of heads/tails of each flip is independent of each other.
Since a coin has 2 sides, H or T, then the probability of:
Heads is 1/2
Tails is 1/2
You flip 6 times.
You want 4 tails and rest 2 should be heads, of course! Thus, you want:
T T T T H H
Each of these individual probabilities are 1/2. So, we have;
[tex]P(4T)\text{ = (1/2)\textasciicircum{}6=}\frac{1}{64}[/tex]