Question

graph the following line passing through -1 and 4 whose slope is m equals 1/4

Answer 1

Answer:

The point-slope form of the equation of a line is generally given as;

$y-y_1=m(x-x_1)$

From the question, we're told that the slope, m, is 1/4 and the line passes through -1 and 4, so our x1 = -1 and y1 = 4, let's substitute these values into the above equation to determine the equation of the line;

$\begin{gathered} y-4=\frac{1}{4}\lbrack x-(-1)\rbrack \\ y-4=\frac{1}{4}(x+1) \\ 4y-16=x+1 \\ 4y=x+17 \\ y=\frac{1}{4}x+\frac{17}{4} \end{gathered}$

So the line will have a y-intercept at 17/4. See below the graph of the line;