Using the trigonometric ratio:
[tex]\cos \Theta=\frac{adjacent}{hypotenuse}[/tex]fromthe question, theta = 45 adjacent = a and hypotenuse = 4
substitute the values and evaluate
[tex]\cos 45=\frac{a}{4}[/tex]cross-multiply
a = 4 cos 45
a = 2.83
a ≈ 2.8 to the nearest tenth
To find b
adjacent = 5 opposite = b and theta =60
Using the trig. ratio
[tex]\tan \Theta=\frac{opposite}{adjacent}[/tex][tex]\tan 60=\frac{b}{5}[/tex]cross-multiply
b= 5 tan 60
b=8.66
b≈ 8.7 to the nearest tenth