Respuesta :

Let:

[tex]\begin{gathered} kFC=JG \\ where \\ k=scale_{\text{ }}factor \\ k19=60.2 \\ so\colon \\ k=\frac{60.2}{19} \\ k=\frac{301}{95} \end{gathered}[/tex]

Therefore:

[tex]\begin{gathered} kFE=IJ \\ \frac{301}{95}\cdot39=IJ \\ IJ=123.6 \end{gathered}[/tex]

RELAXING NOICE
Relax