Question

the sum of two consecutive even numbers is 126 can you help me find the product numbers

Answer 1

Let:

n1 = First even number

n2 = Second even number

The numbers are even and they are consecutive, so:

$\begin{gathered} n1=2n \\ n2=2n+2 \\ n\in N \end{gathered}$$\begin{gathered} 2n+2n+2=126 \\ \text{solve for n:} \\ 4n+2=126 \\ 4n=126-2 \\ 4n=124 \\ n=\frac{124}{4} \\ n=31 \\ ------ \\ so\colon \\ n1=2(31)=62 \\ n2=2(31)+2=64 \end{gathered}$

The product of those numbers is:

$62\times64=3968$