Given
18 red marbles
10 blue marbles
A total of 28 marbles
With replacement
[tex]\begin{gathered} P(RR)=\frac{\text{total number of red marbles}}{\text{total number of marbles}}\cdot\frac{\text{total number of red marbles}}{\text{total number of marbles}} \\ P(RR)=\frac{18}{28}\cdot\frac{18}{28} \\ P(RR)=\frac{324}{784} \\ P(RR)=0.413265 \end{gathered}[/tex]Rounding to the nearest 2 decimal places, the probability with replacement is 0.41.
Without replacement
[tex]\begin{gathered} P(RR)=\frac{\text{total number of red marbles}}{\text{total number of marbles}}\cdot\frac{\text{total number of red marbles left}}{\text{total number of marbles left}} \\ P(RR)=\frac{18}{28}\cdot\frac{17}{27} \\ P(RR)=\frac{306}{756} \\ P(RR)=0.40476 \end{gathered}[/tex]Rounding to the nearest 2 decimal places, the probability is 0.40.