A) list all possible rational rootsB) use synthetic division to test several possible rational roots in order to identify one actual root

Part A
The possible rational roots of a polynomial are all the fractions:
[tex]\frac{p}{q}[/tex]where p is a factor of the constant term and q is a factor of the leading coefficient (the constant multiplying the higher power or x).
Thus, for the equation:
[tex]x^4+2x^3-10x^2-18x+9=0[/tex]we have:
• constant term: ,9
,• factors of 9:, ±1, ±3, ±9
• leading coefficient: ,1
,• factors of 1: ,±1
Therefore, the possible rational roots of this polynomial are:
[tex]\begin{gathered} \pm\frac{1}{1},\pm\frac{3}{1},\pm\frac{9}{1} \\ \\ -9,-3,-1,1,3,9 \end{gathered}[/tex]Part B
The remainder from the division of a polynomial by (x-a), if a is a root, should be zero. Then, we need to test the possible rational roots using long division until we find a remainder equal to 0.
For a = 3, we obtain:
x³ + 5x² + 5x -3
x - 3 ) x⁴+2x³ -10x² -18x +9
x⁴ -3x³
5x³ -10x² -18x + 9
5x³ -15x²
5x² -18x + 9
5x² -15x
-3x + 9
-3x + 9
0
Thus, since the remainder for the above division is 0, 3 is a root of the polynomial.