Question 1 (The line through (3, 8) and (-3, 4) in slope-intercept form)
In writing an equation in slope-intercept form, it is important to solve first for the slope of the line. The slope of the line m can be solved using the equation
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]We have the points (3, 8) and (-3, 4). Substitute the corresponding values on the equation above and solve. We have
[tex]m=\frac{4-8}{-3-3}=\frac{-4}{-6}=\frac{2}{3}[/tex]The slope-intercept form of the equation is generally written as
[tex]y=mx+b[/tex]Use one of the points given in the problem and the calculated m. Substitute this on the equation above to solve for b. I will use (3, 8). We have
[tex]\begin{gathered} 8=\frac{2}{3}(3)+b \\ b=8-2 \\ b=6 \end{gathered}[/tex]Hence, the equation of the line is
[tex]y=\frac{2}{3}x+6[/tex]Question 2 (The line through (-5, 4) with slope 2/3 in point-slope form)
The point-slope form of a line is described as
[tex]y-y_1=m(x-x_1)[/tex]Given the slope and the point (-5, 4), we just substitute this on the equation above. The point-slope form is written as
[tex]\begin{gathered} y-4=\frac{2}{3}(x-(-5)) \\ y-4=\frac{2}{3}(x+5) \end{gathered}[/tex]Or we can also rewrite this as
[tex]y-4=\frac{2}{3}x+\frac{10}{3}[/tex]Question 3 (The line with y-intercept 2 through the point (4, 1) in slope-intercept form)
In this problem, the y-intercept is given. The y=intercept is represented as b. We also have a point (4, 1). We can solve for the value of the slope of this line using the equation
[tex]y=mx+b_{}[/tex]Solving for m, we have
[tex]\begin{gathered} 1=m(4)+2 \\ 4m=1-2 \\ 4m=-1 \\ m=-\frac{1}{4} \end{gathered}[/tex]Hence, the slope-intercept form of the line is written as
[tex]y=-\frac{1}{4}x+2[/tex]