Question

if k=3, evaluate the following function [7(k+6)]/(k to the second power) +k to the 3 power)

Answer 1

$\frac{7(k+6)}{k^2}+k^3$

With k = 3

$\frac{7(3+6)}{3^2^{}}+3^3=\frac{7\cdot9}{9^{}}+27=\frac{63}{9}+27=7+27=34$

The answer is 34