The sine of the interior angle is and what is the value of x

TIP
This is a polygon called pentangon 5sides
N is number of sides
STEP 1
The sum of interior angles of a polygon is
[tex]\begin{gathered} =(n-2)\times180^0 \\ \text{pentangon number of sides is 5} \\ =(5-2)\times180^0 \\ =3\times180^0 \\ =540^0 \end{gathered}[/tex]STEP 2
[tex]\begin{gathered} TO\text{ FIND THE VALUE OF X} \\ 104^0+120^0+140^0+112^0+x=540^0 \\ 476^0+x=540^0 \\ x=540^0-476^0 \\ x=64^0 \end{gathered}[/tex]THE VALUE OF X IS 64 DEGREE