Respuesta :

We want to rewrite the following logarithm

[tex]\log_b\sqrt{6x}[/tex]

To rewrite this logarithm, first let's rewrite the argument of the logarithm. Using the following property

[tex]\sqrt{a}=a^{\frac{1}{2}}[/tex]

We can rewrite our expression as

[tex]\operatorname{\log}_b\sqrt{6x}=\operatorname{\log}_b6x^{\frac{1}{2}}[/tex]

Using the following property

[tex]\log_nx^m=m\log_nx[/tex]

We can rewrite our expression as

[tex]\operatorname{\log}_b6x^{\frac{1}{2}}=\frac{1}{2}\operatorname{\log}_b6x[/tex]

and finally, using the logarithm property of a product

[tex]\log_n(x\cdot y)=\log_nx+\log_ny[/tex]

We can rewrite our expression as

[tex]\begin{gathered} \frac{1}{2}\operatorname{\log}_b6x=\frac{1}{2}\operatorname{\log}_b(6\cdot x) \\ =\frac{1}{2}(\log_b6+\log_bx) \end{gathered}[/tex]

and this is the final form of our expression.

[tex]\operatorname{\log}_b\sqrt{6x}=\frac{1}{2}(\log_b6+\log_bx)[/tex]

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