Question

From the top pf a vertical cliff 50 m high, the angle of depression of an object is 38ᴼ. how far is the object from the base of the cliff?

Answer 1

$64\:m\:(approximately)$

1) We can sketch a triangle for that problem, angles of depression/elevation are usually found by applying the tangent ratio

$\begin{gathered} \tan(38)=\frac{50}{x} \\ x\tan(38)_=50 \\ \frac{x\tan(38)}{\tan(38)}=\frac{50}{\tan(38)} \\ x=63.9970\approx64\:m \end{gathered}$

Rounding off to the nearest whole we can tell the answer is:

$64\:m\:(approximately)$