ANSWER
The surface area is 473 m²
EXPLANATION
To find the surface area we have to find the area of each face of the pyramid. This pyramid has 5 faces: 4 are triangles and 1 (the base) is a square.
The area of each triangular face is:
[tex]A_{\text{triangular face}}=\frac{b\cdot h}{2}=\frac{16m\times11m}{2}=\frac{176}{2}m^2=88m^2[/tex]
The area of the square base:
[tex]A_{\text{square}}=\text{side length}^2=(11m)^2=11^2m^2=121m^2[/tex]
The total surface area of the pyramid is:
[tex]\begin{gathered} S=4\cdot A_{\text{triangular face}}+A_{square} \\ S=4\cdot88m^2+121m^2 \\ S=352m^2+121m^2 \\ S=473m^2 \end{gathered}[/tex]
