Use the equation of f(x) below to evaluate the following: x?, x < 0 f(x)= {2, 03 4. f(-4) 5. f(3) 6. f(12) 0

For point 4. Since -4 is less than zero, that is
[tex]-4<0[/tex]then to find f(-4) replace x = -4 into x², like this
[tex]\begin{gathered} f(-4)=(-4)^2 \\ f(-4)=16 \end{gathered}[/tex]For point 5. Since 3 is in the interval
[tex]0\le x\le3[/tex]then
[tex]f(3)=2[/tex]Finally, for point 6. Since 12 is greater than 3, that is
[tex]12>3[/tex]then to find f(12) replace x = 12 into 4-x, like this
[tex]\begin{gathered} f(12)=4-12 \\ f(12)=-8 \end{gathered}[/tex]