Question

Find the domain 4√x^2 + 3xIndex = 4 & x^2 + 3x under the radical

Answer 1

Answer:

$\text{ Domain: }\lbrack0,\infty)_{}$

Explanation: Assuming that the Domain contains real values:

$D\in\mathfrak{\Re }$

In that case, the domain would be:

$\begin{gathered} f(x)=4\sqrt[\square]{x^2+3x} \\ \text{ Radical can not be negative:} \\ \therefore\Rightarrow \\ x^2+3x\ge0 \\ x^2\ge3x\Rightarrow x\ge3 \\ \text{ Domain: }\lbrack0,\infty)_{} \end{gathered}$