Given:
[tex]x^2=12[/tex]Let's find the solutions.
To find the solutions, take the square root of both sides:
[tex]\sqrt{x^2}=\pm\sqrt{12}[/tex]Now, let's simplify the expression on the right:
[tex]\begin{gathered} x=\pm\sqrt{12} \\ \\ x=\pm\sqrt{3*4} \\ \\ x=\pm\sqrt{3*2^2} \\ \\ x=\pm2\sqrt{3} \end{gathered}[/tex]Therefore, the solutions to the equation is:
[tex]x=\pm2\sqrt{3}[/tex]ANSWER: D
[tex]x=\pm2\sqrt{3}[/tex]