[tex]\begin{gathered} \frac{AB}{BC}\text{ = }\frac{PQ}{RQ} \\ \frac{AB}{6}=\text{ }\frac{9}{11} \\ 11AB\text{ = 9}\times6 \\ AB\text{ = }\frac{54}{11}\text{ = 4.9} \\ \\ \text{lets find, AC} \\ \frac{AC}{CB}\text{ = }\frac{PR}{RQ} \\ \frac{AC}{6}\text{ =}\frac{13}{11} \\ 11AC\text{ = 13 }\times6 \\ AC\text{ = }\frac{78}{11}\text{ = 7} \\ \end{gathered}[/tex]
To now find the perimeter of ABC
AB + BC + AC
4.9 +6 +7 = 17.9 approximately 18
