Question

You have found the following ages (in years) of 5 zebras. Thosezebras were randomly selected from the 42 zebras at your localZOO:8, 11, 17,17, 7, 19Based on your sample, what is the average age of the zebras?What is the standard deviation? Round your answers to thenearest tenth.Average age:Get 3 of 4 questions to level up to FamiliarО о оCheck

Answer 1

We will have the following:

First, we will have that the apparent mean is:

$\begin{gathered} x=\frac{8+11+17+17+7+19}{6}\Rightarrow x=\frac{79}{6} \\ \\ \Rightarrow x\approx13.2 \end{gathered}$

Now, we calculate the standard deviation:

$\begin{gathered} s=\sqrt{\frac{1}{N-1}\sum_{i=1}(x_i-x)^2} \\ \\ \Rightarrow s=\sqrt{\frac{1}{6-1}\sum(x_i-\frac{79}{6})^2}\Rightarrow s\approx5.2 \end{gathered}$

So, the standard deviation is approximately 5.2.