Question

I need help with finding angle measurements in an isosceles trapezoid

Answer 1

In an isosceles trapezoid, the base angles are congruent, so the angle ∠1 is congruent to the angle 88°, so we have ∠1 = 88°.

Also, In any trapezoid, the consecutive angles in each base are supplementary, so we have:

$\begin{gathered} 88+\angle3=180 \\ \angle1+\angle2=180 \end{gathered}$

Solving these equations for ∠2 and ∠3, we have:

$\begin{gathered} 88+\angle3=180 \\ \angle3=180-88 \\ \angle3=92 \\ \\ \angle1+\angle2=180 \\ 88+\angle2=180 \\ \angle2=180-88 \\ \angle2=92 \end{gathered}$

So we have that ∠2 = 92° and ∠3 = 92°.