This graph represents the system of equations below: What is the solution (the values of x and y that are true for both equations)? Fill in the coordinates of the ordered pair:

Explanation
[tex]\begin{gathered} 3x+4y=22 \\ 2x+6y=22 \end{gathered}[/tex]Step 1
isolate x in both equations
[tex]\begin{gathered} 3x+4y=22 \\ 3x=22-4y \\ x=\frac{22}{3}-\frac{4}{3}y \\ \text{and} \\ 2x+6y=22 \\ 2x=22-6y \\ x=\frac{22}{2}-\frac{6}{2}y \\ x=11-3y \end{gathered}[/tex]Step 2
x= x, then
[tex]\begin{gathered} \frac{22}{3}-\frac{4}{3}y=11-3y \\ -\frac{4}{3}y+3y=11-\frac{22}{3} \\ y(-\frac{4}{3}+3)=\frac{11}{3} \\ y(\frac{5}{3})=\frac{11}{3} \\ y=\frac{11}{3}\cdot\frac{3}{5} \\ y=\frac{11}{5} \end{gathered}[/tex]Step 3
finally, replace the y-value to find x
[tex]\begin{gathered} x=11-3y \\ x=11-3\cdot\frac{11}{5} \\ x=11-\frac{33}{5} \\ x=\frac{22}{5} \end{gathered}[/tex]I hope this helps you