Question

What is the solution set of the equation x^2 + 3x - 4 = 6A. (-5, 2)
B. (-2, -1)
C. (2,7)
D. (5, 10)

Answer 1

Step 1

Given;

$x^2+3x-4=6$

Required; To find the solution set

Step 2

To solve we will have;

$\begin{gathered} x^2+3x-4-6=0 \\ x^2+3x-10=0 \end{gathered}$$\begin{gathered} x^2+5x-2x+10=0 \\ x(x+5)-2(x+5)=0 \\ (x-2)(x+5)=0 \\ x=(-5,2) \end{gathered}$

Answer; Option A

$x=(-5,2)$