Question

Question 9 of 10 Select the two values of x that are roots of this equation. x + 3X-6=0 A. x = -3-15 2 B. X= -3+55 2 13 C. X= -3-133 2. O D. -3+√15 2

Answer 1

Given:

$x^2+3x-6=0$

This is of the form

$ax^2+bx+c=0$

where a=1, b=3 and c=-6.

Using the quadratic formuls.

$x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Substitute a=1, b=3, and c=-6 in the formula, we get

$x=\frac{-3\pm\sqrt[]{3^2-4(1)(-6)}}{2(1)}$

$x=\frac{-3\pm\sqrt[]{9+24}}{2}$

$x=\frac{-3\pm\sqrt[]{33}}{2}$

Hence the roots of the given equation are

$x=\frac{-3+\sqrt[]{33}}{2},x=\frac{-3-\sqrt[]{33}}{2}$

Options B and C are correct.