Question

Rewrite the following equation and slope-intercept form.19x-11y= 7Write your answer using integers, proper fractions, and improper fractions in simplest form.

Answer 1

Answer:

The slope-intercept form of the given equation is;

$y=\frac{19}{11}x-\frac{7}{11}$

Explanation:

The slope-intercept form of a line equation is written in the form;

$y=mx+b$

Where;

m is the slope

b is the intercept on the y axis.

We want to transform the given equation to the form above;

$19x-11y=7$

firstly let us subtract 19x from both sides;

$\begin{gathered} 19x-19x-11y=7-19x \\ -11y=-19x+7 \end{gathered}$

Then let us divide both sides by -11;

$\begin{gathered} \frac{-11y}{-11}=\frac{-19x+7}{-11} \\ y=\frac{-19x}{-11}+\frac{7}{-11} \\ y=\frac{19}{11}x-\frac{7}{11} \end{gathered}$

Therefore, the slope-intercept form of the given equation is;

$y=\frac{19}{11}x-\frac{7}{11}$