Question

sovle for x round to the nearest tenth 19 32 g h

Answer 1

SOLUTION

The figure below is a right-angled triangle. To find angle x, we will apply the trig-ratio, that is SOHCAHTOA

Which is

$\begin{gathered} \text{SOH sin}\theta=\frac{opposite}{\text{hypotenuse}} \\ \text{CAH cos}\theta=\frac{adjacent}{\text{hypotenuse}} \\ \text{TOA tan}\theta=\frac{opposite\text{ }}{\text{adjacent }} \end{gathered}$

But we will make use of SOH, we have

$\begin{gathered} \text{ }\sin x=\frac{opposite}{\text{hypotenuse}} \\ \text{ }\sin x=\frac{19}{32} \\ \sin x=0.59375 \\ x=\sin ^{-1}0.59375 \\ x=36.42357 \end{gathered}$

Hence, the answer is 36.4 to the nearest tenth