Question

Find the numerical value if x=4 and y=34x2(squared)+7y=?

Answer 1

To find the numerical value of the expression, we have to replace the variables for their given values. This way:

$\begin{gathered} 4x^2+7y \\ 4(4)^2+7(3) \\ 4\cdot16+21 \\ 64+21 \\ 85 \end{gathered}$

The numerical value of the expression is 85.