What is the diameter of a sphere with a volume of 80487 in^3, to the nearest tenth ofan inch?

EXPLANATION
If the volume of a sphere is 80487 in^3, the diameter would be given by the following relationship:
[tex]\text{Volume}=\frac{4}{3}\cdot\pi\cdot r^3[/tex]Replacing terms:
[tex]80487=\frac{4}{3}\cdot\pi\cdot r^3[/tex]Isolating r^3:
[tex]\frac{80487}{\pi}\cdot\frac{3}{4}=r^3[/tex]Applying the cubic root to both sides:
[tex]\sqrt[]{\frac{80487}{\pi}\cdot\frac{3}{4}}=r[/tex]Switching sides:
[tex]r=\sqrt[]{\frac{80487}{\pi}\cdot\frac{3}{4}}[/tex]Multiplying numbers:
[tex]undefined[/tex]