Given that:
A) Energy,
[tex]E_B=\text{ 2000 J}[/tex]The time is
[tex]\begin{gathered} t_B=3\text{ min} \\ =3\times60\text{ s} \\ =180\text{ s} \end{gathered}[/tex]B) Energy,
[tex]E_C=2\text{ J}[/tex]and time
[tex]t_C=0.1\text{ s}[/tex]C) Energy
[tex]E_A=20\text{ J}[/tex]and time
[tex]t_A=0.5\text{ s}[/tex]
We have to find the power for all three cases.
The formula to calculate power is
[tex]P=\frac{E}{t}[/tex]The power transferred by Bob will be
[tex]\begin{gathered} P_B=\frac{E_B}{t_B} \\ =\frac{2000}{180} \\ =11.11\text{ W} \end{gathered}[/tex]The power transferred by Carl will be
[tex]\begin{gathered} P_C=\frac{E_C}{t_C} \\ =\frac{2}{0.1} \\ =20\text{ W} \end{gathered}[/tex]The power transferred by Alan will be
[tex]\begin{gathered} P_A=\frac{E_A}{t_A} \\ =\frac{20}{0.5} \\ =40\text{ W} \end{gathered}[/tex]Thus, Alan exhibits more power.
