Question

Vector v has an initial point at (8, 4) and a terminal point at (−8, 10). What is -1/2 times vector v?

Answer 1

In order to find a vector multiplication by a scalar, we follow the rule:

$u\ast(n_1,n_2)_\Rightarrow(un_{1,}un_2)$

then, if we apply it to the vector v, we need to find the dimensions of the vector, for that we subtract the initial point from the terminal point,

$(-8-8,10-4)\Rightarrow(-16,6)$

then, multiply by the scalar -1/2,

$-\frac{1}{2}\ast(-16,6)\Rightarrow(8,-3)$

Answer:

$(8,-3)$