Given:
[tex]\frac{1}{4}b^2=16[/tex]is given.
Required:
We need to solve the equation by factoring.
Explanation:
[tex]\frac{1}{4}b^{2}=16[/tex]now add both side negative 16
[tex]\begin{gathered} \frac{1}{4}b^2-16=16-16 \\ \\ \frac{1}{4}b^2-16=0 \\ \\ (\frac{1}{2}b-4)(\frac{1}{2}b+4)=0 \end{gathered}[/tex]further simplify as:
[tex]\begin{gathered} (\frac{1}{2}b+4)=0\text{ or \lparen}\frac{1}{2}-4)=0 \\ \\ b=-8 \\ or \\ b=8 \end{gathered}[/tex]Final answer:
b=8 or b=-8