Question

What is the value of x in the following equation?√2x=4

Answer 1

sidessidesGiven equation is,

$\sqrt[]{2}x=4$

Now, solving the given equation,

$\begin{gathered} \frac{\sqrt[]{2}}{\sqrt[]{2}}x=\frac{4}{\sqrt[]{2}} \\ x=\frac{4}{\sqrt[]{2}}.\frac{\sqrt[]{2}}{\sqrt[]{2}} \\ x=\frac{4\sqrt[]{2}}{2}\lbrack\sqrt[]{2\text{ }\cdot}\sqrt[]{2}=2\rbrack \\ x=2\sqrt[]{2} \end{gathered}$

So, the required solution is,

$x=2\sqrt[]{2}$

Squaring both side we get,

$\begin{gathered} x^2=(2\sqrt[]{2})^2 \\ x^2=4\cdot2 \\ x^2=8 \end{gathered}$