Together two computers cost $2700 per year to rent. If one costs twice as much as theother, what is the monthly cost of the most expensive one?OA. $900OB. $1,800OC. $225OD. $150OE. $75

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The Solution:

Given:

Let the yearly cost of one computer be x.

And that of the other computer be 2x.

The total cost of renting the two computers = $2700

[tex]\begin{gathered} x+2x=2700 \\ 3x=2700 \\ x=\frac{2700}{3}=900=\text{ \$}900 \end{gathered}[/tex]

So, the most expensive one will cost:

[tex]Most\text{ expensive computer}=2x=2\times900=\text{\$}1800[/tex]

Therefore, the correct answer is [option B]

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