To solve this question first open the brackets on the right-hand side
[tex]4(1-5x)=4-20x[/tex]Then re-write the equation as
[tex]-16-10x=4-20x[/tex]Collect the like terms,the terms with x's and those with no x's
[tex]-16-4=-20x+10x\text{ }[/tex]Apply addition
[tex]-20=-10x[/tex]Apply division by dividing both sides of the equation by -10 to get the value of x
[tex]\frac{-20}{-10}=\frac{-10x}{-10}[/tex][tex]2=x[/tex]The answer is x=2
