Question

Two turns contain vhite balls and yellow balls. The first urn contains 7 white balls and 10 yellowballs and the second turn contains 8 white balls and 2 yellow balls. A ball is drawn at randomfrom each turn. What is the probability that both balls are white?

Answer 1

Answer:

28/85

Explanation:

First Urn

Total number of balls = 7+10 =17

Number of white balls =7

P(White) = 7/17

SecondUrn

Total number of balls = 8+2=10

Number of white balls =8

P(White) = 8/10

Therefore, if a ball is drawn at random from each urn, the probability that both balls are white will be:

$\begin{gathered} =\frac{7}{17}\times\frac{8}{10} \\ =\frac{56}{170} \\ =\frac{28}{85} \end{gathered}$