The given system is-
[tex]\mleft\{\begin{aligned}7x-3y=-25 \\ 4x+5=y\end{aligned}\mright.[/tex]To solve it by substitution, we just have to replace the second equation in the first one.
[tex]7x-3(4x+5)=-25[/tex]Now we solve for x.
[tex]\begin{gathered} 7x-12x-15=-25 \\ -5x=-25+15 \\ -5x=-10 \\ x=\frac{-10}{-5} \\ x=2 \end{gathered}[/tex]Then, we use x value to find y.
[tex]\begin{gathered} y=4x+5 \\ y=4(2)+5=8+5 \\ y=13 \end{gathered}[/tex]