=Solve this system of equations byusing the elimination method.2x – 3y = 255x + 3y = 10([?], 1)=The ordered pair of solutionsis written in the format (x, y).

Given:
[tex]\begin{gathered} 2x-3y=25.............\left(1\right) \\ 5x+3y=10..............\left(2\right) \end{gathered}[/tex]To find: The solutions
Explanation:
Adding equation (1) and (2) we get,
[tex]\begin{gathered} 2x-3y+5x+3x=25+10 \\ 7x=35 \\ x=5 \end{gathered}[/tex]Substitutte the value x = 5 in equation (1), we get
[tex]\begin{gathered} 2\left(5\right)-3y=25 \\ 10-3y=25 \\ -3y=25-10 \\ -3y=15 \\ y=\frac{15}{-3} \\ y=-5 \end{gathered}[/tex]Hence, the solutions are
[tex]x=5,y=-5[/tex]Final answer: The ordered pair of solutions is,
[tex]\lparen5,-5)[/tex]