Question

I2 + KIO3 + HCl ----- ICl + KCl + H2O Balance this equation, tell me how many grams of KCl will be produced from 160 grams of HCl? also How many moles of iodine are needed to produce 3.4 moles of water?

Answer 1

Explanation

Given

Mass of HCl = 160 g

Moles of water = 3.4 mol

Required: Balance the equation, Find mass of KCl and find moles of iodine.

Solution

Step 1: Balance the equation

$2I_2+KIO_3+6HCl\rightarrow5ICI+KCl+3H_2O$

Step 2: Find the number of moles of HCl

n = m/M

n = 160g/36,458 g/mol

n = 4.39 mol

Step 3: Find the moles of KCl using stoichiometry

The molar ratio between HCl and KCl is 6:1

Therefore moles of KCl = 4.93 x (1/6) = 0.731 mol

Step 4: Calculate the mass of KCl

m = n x M

m = 0.731 mol x 74,5513 g/mol

m = 54.53 g

Step 4: Use the moles of water to find the moles of iodine

The molar ratio between iodine and water is 2:3

Therefore the moles of iodine = 3.4 x (2/3) = 2.27 moles

Answers

Mass of KCl = 54.53 g

Moles of iodine = 2.27 moles