Question

A student measures the molar solubility of silver sulfite in a water solution to be 1.53x10-5M. Based on her data , the solubility product constant for this compound is

Answer 1

ANSWER:

EXPLANATION

Given that:

$\text{ The molar solubility of silver sulfide is 1.53 x 10}^{-5}$

To find the solubility constant product for the compound, follow the steps below

Step 1: Write the ionic equation for silver sulfite

$Ag_2SO_3\rightarrow\text{ 2Ag}^+\text{ + SO}_3^{2-}$

From the above reaction, the silver sulfite split into silver ion and sulfite ion

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