Question

3,12,48,...t8find the 5th term

Answer 1

Hello

This is a geometric progression and we have the first term and we have to find the common ratio.

first term = a

common ratio = r

$\begin{gathered} a=3 \\ r=\frac{12}{3}=4 \end{gathered}$

The 5th term would be

$\begin{gathered} T_5=ar^4 \\ T_5=3\times4^4 \\ T_5=3\times256 \\ T_5=768 \end{gathered}$

The value of the 5th term of the sequence is 768