Question

can you please help i cant seem to find the answer

Answer 1

Answer:

PA = 118800 Pa

PB = 148500 Pa

Force exerted on face A = 4276800 N

Force exerted on face B = 534600 N

Explanation:

The pressure can be calculated as:

$P=\rho gh$

Where ρ is the density of water, g is the gravity and h is the height.

The density of water is 1000 kg/m³ and the gravity is g = 9.9 m/s².

Then, the height for A is

2d = 2(6m) = 12 m

And the height for B is:

(2 + 1/2)d = 2(6m) + 1/2(6m) = 15 m

Therefore, each pressure is equal to:

$\begin{gathered} PA=\frac{1000\operatorname{kg}}{m^3}(\frac{9.9m}{s^2})(12m)=118800Pa \\ PB=\frac{1000\operatorname{kg}}{m^3}(\frac{9.9m}{s^2})(15m)=148500Pa \end{gathered}$

Then, the force at each face is equal to the pressure times the area. Since both areas are equal to d² = (6m)² = 36 m², we get that the force exerted on each face are:

$\begin{gathered} F_A=118800Pa(36m^{2})=4276800N \\ F_B=148500Pa(36m^{2})=534600N \end{gathered}$

Therefore, the answers are:

PA = 118800 Pa

PB = 148500 Pa

Force exerted on face A = 4276800 N

Force exerted on face B = 534600 N