Please answer the following question correctly. If the question stated isn’t clear, it states:*In the figure below, the segments EF and EG are tangent to the circle centered at 0. Given thatEG=2.8 and OE =3.5, find OF.*

Given:
EG = 2.8, OE = 3.5,
Required: OF
To solve this problem, we need to apply this rule:
The tangent is always perpendicular to the radius drawn to the point of tangency.
Hence, we can draw:
Let the length of OF be r
Using Pythagoras theorem, we can solve for r
[tex]\begin{gathered} hypothenuse^2\text{ = opposite}^2\text{ + adjacent}^2 \\ 3.5^2\text{ = r}^2+\text{ 2.8}^2 \\ r^2\text{ = 4.41} \\ r\text{ = 2.1} \end{gathered}[/tex]Hence, the length of OF is 2.1